通过SMTP Python发送电子邮件时遇到问题 [英] Having trouble with sending an email through SMTP Python

问题描述

因此，我正在尝试使用Python通过SMTPlib发送电子邮件，但无法正常工作。我阅读了Microsoft SMTP规范，并进行了相应的整理，但无法正常工作。这是我的代码：

So I'm trying to send an email through SMTPlib with Python, but I can't get it to work. I read up on the Microsoft SMTP specs, and put them in accordingly, but I can't get it to work. Here is my code:

    # Send an email
    SERVER  = "smtp-mail.outlook.com"
    PORT    = 587
    USER    = "******@outlook.com"
    PASS    = "myPassWouldBeHere"
    FROM    = USER
    TO      = ["******@gmail.com"]
    SUBJECT = "Test"
    MESSAGE = "Test"
    message = """\
From: %s
To: %s
Subject: %s
%s
""" % (FROM, ", ".join(TO), SUBJECT, MESSAGE)
    try:
        server = smtplib.SMTP()
        server.connect(SERVER, PORT)
        server.starttls()
        server.login(USER,PASS)
        server.sendmail(FROM, TO, message)
        server.quit()
    except Exception as e:
        print e
        print "\nCouldn't connect."

我从键盘记录器中获取了代码，但是我对其进行了一些清理。我在此处上了解了基本SMTP的工作原理，但是却有<$ c这样的东西$ c> starttls （方法）我不太了解。

I got the code from a keylogger, but I cleaned it up a bit. I read up here on how basic SMTP works, but there are few things like starttls (Methods) I don't quite understand.

对此我非常感谢。

推荐答案

尝试一下。这在Python 2.7中有效。

Try this. This works in Python 2.7.

def send_mail(recipient, subject, message):

    import smtplib
    from email.MIMEMultipart import MIMEMultipart
    from email.MIMEText import MIMEText

    username = "[e-mail]"
    password = "sender's password"

    msg = MIMEMultipart()
    msg['From'] = username
    msg['To'] = recipient
    msg['Subject'] = subject
    msg.attach(MIMEText(message))

    try:
        print('sending mail to ' + recipient + ' on ' + subject)

        mailServer = smtplib.SMTP('smtp-mail.outlook.com', 587)
        mailServer.ehlo()
        mailServer.starttls()
        mailServer.ehlo()
        mailServer.login(username, password)
        mailServer.sendmail(username, recipient, msg.as_string())
        mailServer.close()

    except error as e:
        print(str(e))


send_mail('[e-mail]', 'Sent using Python', 'May the force be with you.')

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