确定字节序的最Python方式是什么？ [英] What's the most Pythonic way of determining endianness?

问题描述

我正在尝试找出计算代码运行的机器是大端还是小端的最佳方法。我有一个可行的解决方案（尽管我尚未在大端机上对其进行测试），但似乎有些笨拙：

I'm trying to find the best way of working out whether the machine my code is running on is big-endian or little-endian. I have a solution that works (although I haven't tested it on a big-endian machine) but it seems a bit clunky:

import struct
little_endian = (struct.pack('@h', 1) == struct.pack('<h', 1))

这只是将本地两字节数据包与小字节序数据包进行比较。有没有更漂亮的方法？

This is just comparing a 'native' two-byte pack to a little-endian pack. Is there a prettier way?

推荐答案

答案在 sys模块：

>>> import sys
>>> sys.byteorder
'little'

当然，根据您的计算机，它可能会返回大 。当然，您的方法也应该可以使用。

Of course depending on your machine it may return 'big'. Your method should certainly work too though.

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