预期为“；”在“ for”语句说明符中（iOS） [英] Expected ';' in 'for' statement specifier (iOS)

问题描述

当我在iOS中尝试以下代码进行快速枚举时...

when I try the following code in iOS for fast enumeration...

NSArray *array = [NSArray arrayWithObjects: 
                  @"Hefeweizen", @"IPA", @"Pilsner", @"Stout", nil];

for (NSString *element in array) 
    NSLog(@"Beer: %@", element);

...我收到此错误：

... I get this error:

Expected ';' in 'for' statement specifier

推荐答案

该语法称为快速枚举，是Objective的一部分-C 2.0，因此，如果您运行的是2.0版之前的编译器，它将无法使用。

That syntax is called fast enumeration and is part of Objective-C 2.0, so if you're running a pre-2.0 version of the compiler it won't work.

听起来像是编译器期望的标准语法是这样的：

The standard syntax which it sounds like the compiler is expecting is something like this:

for (int i = 0; i < [array count]; i++) {
    NSString *element = [array objectAtIndex:i];
    NSLog (@"Beer: %@", element);
}

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