从Unix Shell脚本获取当前日期 [英] Get Current date in epoch from Unix shell script

问题描述

如何获取当前日期值，即从1970-1-1开始经过的天数。我需要使用Unix Shell脚本解决方案。

How to get the current date value in epoch i.e., number of days elapsed since 1970-1-1. I need solution in unix shell script.

推荐答案

更新：先前在此处发布的答案链接到自定义脚本不再可用，仅是因为OP指出 date +'％s'对他不起作用。请参阅 UberAlex的答案和 cadrian对于正确的解决方案的答案。简而言之：

Update: The answer previously posted here linked to a custom script that is no longer available, solely because the OP indicated that date +'%s' didn't work for him. Please see UberAlex' answer and cadrian's answer for proper solutions. In short:

1. 对于自Unix时代以来的秒数，请使用 date（1） 如下：

1. For the number of seconds since the Unix epoch use date(1) as follows:

date +'%s'

对于自Unix时代以来的天数，将结果除以一天中的秒数（注意双括号！）：

For the number of days since the Unix epoch divide the result by the number of seconds in a day (mind the double parentheses!):

echo $(($(date +%s) / 60 / 60 / 24))

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