为什么在曼彻斯特编码中，比特率是波特率的一半？ [英] Why In Manchester encoding, the bit rate is half of the baud rate?

问题描述

我认为波特率是符号的速率，如果每个符号包含n位，则位速率应为 nx波特率

I think baud rate is the rate of the symbols, and if each symbol contains n bit, then the bit rate should be n x baud rate

在以太网（曼彻斯特编码）中，如果位速率是波特率的一半，则符号包含1/2位？据我所知，比特率至少应不低于符号率（波特率）。

In Ethernet( Manchester encoding) ,if bit rate is half of the baud rate, then a symbol contains 1/2 bit ? As far as I know, bit rate should at least not less than symbol rate (baud rate).

关于波特率与比特率的关系，我的理解是问题，但涉及曼彻斯特代码时，这完全违反直觉，有人可以解释这些吗？

About the relationship of baud rate and bit rate, my understanding have no problems, yet when it comes to the Manchester code, it's totally counterintuitive, could anyone explain about these?

推荐答案

与比特率有关波特率与符号变化的速度有关，而波特率与符号的变化速度有关，这在模拟信号中是很重要的。这些可以是幅度，频率或相位或更复杂的调制方法。在曼彻斯特编码中，两种不同的电压电平代表一位。因此，假设您要在一秒钟内传输1Mbit数字数据，那么您将需要对模拟信号的电平进行约200万次更改。因此，您的比特率将为1Mbs，而您的波特率将为2M波特。

Bit rate is related to the speed of the transmission of the digital bit, while baudrate is related to the speed of change of symbols, which are significancies in analog signal. These can be either in amplitude, frequency or phase or more complex modulation methods. In manchester encoding, one bit is reprsented by two different levels of voltage. Therefore, lets say if you want to transfer 1Mbit digital data in one second, then you will need to make ~ 2 million changes in the level of the analogous signal. That is why, your bit rate will be 1Mbs, while your baud rate will be 2M bauds.

在NRZ编码中，一位用一个符号表示。这样的利率将是相等的。

In NRZ encoding, one bit is represented by one symbol. Therfore rates will be equal.

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