从用户提供的字符串生成自定义Blockly块,而无需eval [英] Generate a custom Blockly block from a user-provided string without eval
问题描述
我正在使用JavaScript将字符串转换为Google Blockly块.
I am converting a string into a Google Blockly block using JavaScript.
输入字符串类似于"Hello %s World"
-其中%s
定义字符串输入.我需要将其转换为:
The input string is something like "Hello %s World"
- where %s
defines a string input. I need to turn that into:
Blockly.Blocks['blockname'] = {
init: function() {
this.appendDummyInput()
.appendField("Hello ")
.appendField(new Blockly.FieldTextInput("input1"), "")
.appendField(" World");
}
};
但是我不确定在不使用eval()
的情况下如何实现这一目标,并且由于输入字符串来自用户,因此我知道使用eval()
并不是一个好主意.
But I'm not sure how to achieve this without using eval()
, and as the input string is from the user, I understand that using eval()
would not be a good idea.
我当前的代码是:
currentLine = blockText[x].split(/(%s)/);
for( var y = 0; y < currentLine.length; y++ )
{
if( currentLine[y] == "" )
{
//do nothing
}
else if( currentLine[y] == "%s" )
{
//create a input
}
else
{
//create a label
}
}
但是我不确定如何创建所需的Blockly代码,而无需在字符串中构建JavaScript,然后最后使用eval()
.
But I'm not quite sure how to create the Blockly code that I need, without building up the JavaScript in a string and then using eval()
at the end.
有人可以帮我吗?
推荐答案
您可以创建自定义通用块,而无需输入任何类似内容-
You can create a custom generic block without any inputs like below -
Blockly.Blocks['generic_block'] = {
init: function() {
this.jsonInit({
message0: '',
colour: '230'
});
}
};
现在,您可以通过代码创建此块的新实例.根据您的JS字符串解析,您可以在此块内创建输入和字段,如下所示-
Now you can create a new instance of this block though the code. Based on your JS string parsing, you can create the inputs and the fields inside this block as below -
var lineBlock=yourBlocklyWorkspace.newBlock('generic_block'); // create new instance of generic block
var input=lineBlock.appendDummyInput(); // create a dummy input
var blockText="Hello %s World"; // one line of the JS code
var currentLine = blockText.split(/(%s)/); // split every word
for( var y = 0; y < currentLine.length; y++ ) { // loop through each word
if(currentLine[y]==='%s') { // if the word is %s, then append input field
input.appendField(new Blockly.FieldTextInput('input'+y)); // input+y is the name of the field
} else { // else just append label field
var labelField=new Blockly.FieldLabel('label'+y); // label+y is the name of the field
labelField.setValue(currentLine[y]); // set the label value to the word
input.appendField(labelField)
}
}
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