C ++是否可以忽略函数中的异常? [英] Does C++ have a way to ignore an exception from a function?

问题描述

我创建了一个引发异常的函数，但在某些情况下，我希望它简单地忽略此异常.

I created a function that throws an exception, but under some circumstances I want it to simply ignore this exception.

我是这样写代码的，但是不太优雅:

I wrote my code like this, but it's not quite elegant:

try {
    myFunction();
} catch (...) {}

C ++是否有另一种编写方法?

Does C++ another way to write this?

推荐答案

不，没有.

在这种情况下，您可以遵循标准的做法，即两次使用 std :: nothrow_t ，一次也没有.使用后者包装第一个

you can follow what the standard does in this case which is to overload the function twice, once with std::nothrow_t and once without. use the later to wrap the first

std::error_code my_function(std::nothrow_t) noexcept;
void my_function(); //throws

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