访问在应用程序其他部分的构造函数中声明的类变量(反应) [英] Accessing class variable declared in constructor in other parts of the app (React)

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问题描述

我目前正在学习React-native.我正在关注Pluralsight教程,但不幸的是,他的某些代码已过时. 我有以下代码:

I'm currently learning React-native. I am following a Pluralsight tutorial but unfortunately some of his code is out of date. I have the following code:

import Expo from 'expo';
import React from 'react';
import TaskList from './TaskList';
import {
  Component,
  View,
  Navigator,
  Text
} from 'react-native';

class todo extends React.Component {
  constructor(props,context){
    super(props,context);
    this.state ={
      todos: [
        {
          task: 'Task1',
        },
        {
          task: 'Task 2',
        },
      ]
    }
  }
  onAddStarted(){
    this.nav.push({
      name: 'taskform',
        })

  }

  renderScene(route,nav){
    switch(route.name){
      case 'taskform':
      return (
        <Text>Add form comes here!</Text>
      );
      default:
      return(
        <TaskList onAddStarted={this.onAddStarted}
        todos={this.state.todos}/>
      );

    }
  }
  render() {
    return (
    <Navigator initialRoute={{name: 'Tasklist'}}
                ref={((nav)=> {
                  this.nav=nav;
                })}
                renderScene={this.renderScene}/>
    );
  }

}




Expo.registerRootComponent(todo);

我的问题是该行:

    todos={this.state.todos}/>

如果我记录this.state它错误并且状态未定义如果我以内联方式复制待办事项的内容,则代码会编译,因此我知道其范围界定方面的问题,但我想我从根本上不知道如何正确地做到这一点.在开始使用Navigator之前,我可以从构造函数中完全引用this.state.

if i log this.state it errors and state is undefined. If i copy the content of todos inline the code compiles so I know its some problem with scoping but I guess I fundamentally don't understand how to do it properly. Before I started using Navigator I was able to reference this.state from the constructor absolutely fine.

如果有人可以帮助我理解我,我会请她

I would appericiate if someone could help me understand.

谢谢!

推荐答案

您需要提供 renderScene 上下文,以便它可以访问 this 及其状态.为此,您可以在render函数中修改以下行:

You need to give renderScene context, so that it can access this and then its state. To do this you can amend the following line in the render function:

 renderScene={this.renderScene}

 renderScene={this.renderScene.bind(this)}

NB (使用 bind )会生成新功能,这会降低性能(例如,如果要渲染很多项目).因此,一种常见的模式是在构造函数中进行绑定:

N.B. As using bind generates a new function this can degrade performance (for instance if you are rendering a lot of items). So a common pattern is to do the binding in the constructor:

this.renderScene = this.renderScene.bind(this);

如果采用这种方法,则渲染功能可以保持现在的状态.

If you take this approach your render function can stay like it is now.

这篇关于访问在应用程序其他部分的构造函数中声明的类变量(反应)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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