从URL提取字符串的一部分-Java Regex [英] Extract part of a string from a URL - Java Regex

问题描述

我正在尝试提取'/'和'.之间的字符串.网址.例如，我有一个类似"some.com/part1/part2/part3/stringINeed.xyz"的URL.我需要从上面的URL中提取"stringINeed"，即最后一个"/"和."之间的一个.没有其他的.

I'm trying to extract a string between '/' and '.' of a URL. For example, I have a URL like "some.com/part1/part2/part3/stringINeed.xyz". I need to extract "stringINeed" from the above URL, the one between last '/' and the '.' nothing else.

到目前为止，我尝试了以下操作，并给出了空的输出​​:

So far, I tried the following and it gives an empty output:

import java.util.*;
import java.lang.*;
import java.io.*;
import java.util.regex.Pattern;
import java.util.regex.Matcher;

class Extract
{
    public static void main (String[] args) throws java.lang.Exception
    {
        String str = "part1/part2/part3/stringINeed.xyz" ;
        Pattern pattern = Pattern.compile("/(.*?).");
        Matcher matcher = pattern.matcher(str);
        if (matcher.find()) {
     System.out.println(matcher.group(1));
        }
    }
}

我的代码有什么问题.有人可以帮忙吗?

What is wrong with my code. Can anyone help?

推荐答案

使用此正则表达式:

[^/.]+(?=\.[^.]+$)

请参见演示.

在Java中:

Pattern regex = Pattern.compile("[^/.]+(?=\\.[^.]+$)");
Matcher regexMatcher = regex.matcher(subjectString);
if (regexMatcher.find()) {
    ResultString = regexMatcher.group();
} 

说明

• [^/.]+匹配所有不是斜杠或点的字符
• 前瞻(?=\.[^.]+)断言，其后是一个点，后面跟着非点，然后是字符串的结尾

• [^/.]+ matches any chars that are not a slash or a dot
• The lookahead (?=\.[^.]+) asserts that what follows is a dot followed by non-dots and the end of the string

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