如何使用ffmpeg提取视频中第一秒的第一帧? [英] How to extract the very first frame of a second in a video using ffmpeg?

问题描述

我正在尝试从视频中提取一秒钟的第一帧.我尝试了多种方法来实现这一目标，但失败了.这是我尝试的命令.

I am trying to extract the first frame of a second from a video. I have tried different ways to achieve this, but I failed. Here the commands I tried.

ffmpeg -i input.ts -s 400x222 -q:v 3 -start_number 0 -vf fps=1 %d.jpg

稍后，我正在尝试使用特定秒的以下命令再次提取帧.在这里，我提取第210秒的帧.

Later, I am trying to extract the frames again using the below command of that particular second. Here I'm extracting the frames of 210th second.

ffmpeg -ss 210 -i input.ts -s 300x250 -t 1 -start_number 0 images.%d.jpg

我只想提取第二个的开始帧.假设从该特定秒的0.001开始.

I want to extract only the starting frame of the second. Let's say from 0.001 of that particular second.

当我比较第一条命令提取的210秒帧与第二条命令提取的第一帧时完全不同.

When I compare the frame of 210 second extracted by my first command with the first frame extracted by second command are completely different.

为了以后使用，为了避免冲突，我只想提取原始输入视频的第一帧.我尝试使用过去此处中stackoverflow专家告诉过的命令.但是当我运行它时.它仅提取起始帧(仅1帧).

For the later use, to prevent the conflicts I want to extract only the very first frame of the original input video. I tried using the command which was told by stackoverflow experts in the past here. But when I run it. It is only extracting the starting frame(only 1 frame).

如何每秒提取视频的最开始的帧?

How can I extract the very starting frame of the video per every second?

推荐答案

尝试以下命令:

ffmpeg -i input.mp4 -vf "select=between(mod(n\, 25)\, 0\, 0), setpts=N/24/TB" output-%04d.png

您必须在between(mod(n\, 25)\, 0\, 0)中通过视频帧速率或fps，我的视频fps是25，所以我通过25

you have to pass your video framerate or fps in between(mod(n\, 25)\, 0\, 0) my video fps is 25 so i pass 25

如果您的fps为60，则必须在between(mod(n\, 60)\, 0\, 0)

if your fps 60 then you have to pass 60 in between(mod(n\, 60)\, 0\, 0)

如果您想每秒1帧5帧，请使用between(mod(n\, 25)\, 0\, 4)每秒1帧5帧.

also if you want 1st 5 frames of every second then use between(mod(n\, 25)\, 0\, 4) it will give your 1st 5 frames of every second.

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