打开并获取系统文件描述符 [英] fopen and getting system file descriptor

问题描述

当我使用open打开文件时，我想获取返回资源的系统文件描述符.我假设描述符是一个INT值，通常在/dev/fd/

I want to get a system file descriptor of the returned resource when I open a file using open. I assume the descriptor is an INT value which is normally inside /dev/fd/

我知道我可以通过以下操作从描述符中读取内容:

I know that I can read from the descriptor by doing something like:

fread("php://fd/$descriptor", $buflen);

但是现在我想获取由PHP的fopen()打开的资源的描述符.有办法吗?

But now I want to get the descriptor for a resource opened by PHP's fopen(). Is there a way?

推荐答案

这是一个很棘手的解决方法，但是有效！

This is a rather hacky way around it but it works!

function fd($realpath) {
  $dir = '/proc/self/fd/';
  if ($dh = opendir($dir)) {
      while (($file = readdir($dh)) !== false) {
          $filename = $dir . $file;
          if (filetype($filename) == 'link' && realpath($filename) == $realpath) {
            closedir($dh);
            return $file;
          }
      }
      closedir($dh);
  }
  return FALSE;
}

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