如何对一个文本文件中的所有数字求和? [英] How to sum all the numbers in a text file?

问题描述

我必须计算文件中任何数字的总和并打印总和.

I have to calculate the sum of any numbers in the file and print the sum.

数字定义为以0到9开头的数字，然后是0到9任意数目的字符串.

A number is defined as any string beginning with a digit 0 through 9 followed by any number of digits 0 through 9.

字母数字字符串(包括数字和字母的字符串)不包括在求和中.

Alphanumeric strings (strings including both numbers and letters) are not to be included in the summation.

这是文件的内容:

a b cddde ff 1
5
hH five lll 0
l 10
99 abcd7
9kk
0

在这种情况下，答案是115.

So the answer would be 115 in this case.

推荐答案

def function():

    infile = open("test.txt", 'r')
    content = infile.read()       
    infile.close()
    wordList = content.split()

    total = 0

    for i in wordList:
        if i.isnumeric():
            total += int(i)
    return total

在此解决方案中，我将文件命名为test.txt.想法是您遍历wordList，这是一个包含test.txt中拼接的每个项目的列表(尝试在循环之前打印wordList以便自己查看).然后，我们尝试将每个项目都转换为int格式(假定文件中没有小数，如果可以，则可以包括float转换).然后我们捕获ValueError，该错误在将"a"转换为int时引发.

In this solution, I named the file test.txt. The idea is you loop through wordList which is a list containing every item spliced in test.txt (try printing wordList before the loop to see for yourself). We then try to cast each item as a int (this assumes no decimals will be in the file, if so you can include a float cast). We then catch ValueError which gets raised when casting i.e 'a' as an int.

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