如何在Shell脚本中逐行读取文件并将每一行存储在变量中 [英] how to read file line by line in shell script and store each line in a variable

问题描述

我是Unix的新手.我必须编写一个shell脚本，逐行读取文件并将其存储在单独的变量中.我的文本文件包含多个源路径和一个目标路径. 像这样:

i am new in unix. i have to write a shell script which read a file line by line and store it in a separate variable. my text file contents multiple source path and one destination path. something like this::

source_path=abc/xyz
source_path=pqr/abc
desination_path=abcd/mlk

源路径的数量可以变化. 我在Unix方面没有太多经验.谁能帮助我实现这一目标.这将非常有帮助.

number of source path can vary. I dont have much hands on experience in Unix. Can anyone help me to achieve this one. It will be very helpfull.

预先感谢

推荐答案

sourcePaths=( $(grep source_path myfile |cut -d= -f2) )
destPath=`grep destination_path myfile |cut -d= -f2`

$sourcePaths是source_path s的数组.您无需将每个source_path存储在单独的变量中.

$sourcePaths is an array of source_paths. You don't need to store each source_path in a separate variable.

您可以遍历数组，并对每个source_path执行所需的操作.例如:

You can loop over the array and do what you want with each source_path. For example:

for i in "${sourcePaths[@]}"
do
    echo $i
done

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