仅文件复制x文件扩展名 [英] File copy only x file extension
问题描述
我有一个可以复制文件的有效方法,但是我想为其添加一个额外的功能.
我只想复制以下文件扩展名:*.mp4
,*.LRV
和*.THM
.
I have a working method which copies my files, but I want to add a extra function to it.
I want to copy only these file extensions:*.mp4
, *.LRV
and *.THM
.
您可以在下面看到有2个方法和一个if ..因此有3个方法(未复制第一个方法的所有内容,因为它们不相关).
You can see below that there are 2 methodes and a if.. so there are 3 methodes(did not copy everything of the first methode because it issn't relevant).
其他一些人告诉我,我需要添加: var extensions = new [] {".MP4",".LRV",".THM"}; var files1 = Directory.GetFiles(GoPro1).Where(file => extensions.Contains(new FileInfo(file).Extension)); 对于第一种方法..但这不是正确的,我得到下一个错误:无法从'String []'转换为'String'"
Some other guy told me that i need to add: var extensions = new[] { ".MP4", ".LRV", ".THM" }; var files1 = Directory.GetFiles(GoPro1).Where(file => extensions.Contains(new FileInfo(file).Extension)); To the first methode.. but this issn't right i get the next error:"Cannot convert from 'String[]'to'String'"
我认为我需要在方法中添加一个循环:copyall.但是我不知道我必须做什么样的循环.有人可以帮我解决这个问题吗?
I think i need to add a loop in the methode: copyall. But i don't know what kind of loop i must make. can someone please help me out with this problem?
if (dlg.ShowDialog() == System.Windows.Forms.DialogResult.OK)
{
Locatie = dlg.SelectedPath;
var extensions = new[] { ".MP4", ".LRV", ".THM" };
var files1 = Directory.GetFiles(GoPro1).Where(file => extensions.Contains(new FileInfo(file).Extension));
Copy1(files1, Locatie + @"\" + "GoPro1");
}
public void Copy1(string sourceDirectory, string targetDirectory){
DirectoryInfo diSource = new DirectoryInfo(sourceDirectory);
DirectoryInfo diTarget = new DirectoryInfo(targetDirectory);
//Gets size of all files present in source folder.
GetSize(diSource, diTarget);
maxbytes = maxbytes / 1024;
progressBar1.Maximum = maxbytes;
CopyAll(diSource, diTarget);
}
public void CopyAll(DirectoryInfo source, DirectoryInfo target)
{
if (Directory.Exists(target.FullName) == false)
{
Directory.CreateDirectory(target.FullName);
}
foreach (FileInfo fi in source.GetFiles())
{
fi.CopyTo(Path.Combine(target.ToString(), fi.Name), true);
total += (int)fi.Length;
copied += (int)fi.Length;
copied /= 1024;
progressBar1.Step = copied;
progressBar1.PerformStep();
label1.Text = (total / 1048576).ToString() + "MB van de " + (maxbytes / 1024).ToString() + "MB gekopieërd";
label1.Refresh();
}
foreach (DirectoryInfo diSourceSubDir in source.GetDirectories())
{
DirectoryInfo nextTargetSubDir = target.CreateSubdirectory(diSourceSubDir.Name);
CopyAll(diSourceSubDir, nextTargetSubDir);
}
MessageBox.Show("Het kopieren is klaar!");
}
推荐答案
解决了!
在最后一个方法中:Copyall: foreach(source.GetFiles("*.MP4")中的FileInfo fi) {
In the last methode: Copyall: foreach (FileInfo fi in source.GetFiles("*.MP4")) {
fi.CopyTo(Path.Combine(target.ToString(), fi.Name), true);
total += (int)fi.Length;
copied += (int)fi.Length;
copied /= 1024;
progressBar1.Step = copied;
progressBar1.PerformStep();
label1.Text = (total / 1048576).ToString() + "MB van de " + (maxbytes / 1024).ToString() + "MB gekopieërd";
label1.Refresh();
}
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