如何从文件路径中删除％20? [英] How to remove %20 from the file path?

问题描述

file:///home/ashu/Music/Collections/randomPicks/ipod%20on%20sep%2009/Coldplay-Sparks.mp3

如何转换上述字符串以获取可以传递给open()函数的普通文件路径?

How can I convert a string like the above to get the normal file path which I can pass to open() function?

推荐答案

看看 url2pathname :

import urllib2

path = urllib2.url2pathname("file:///home/ashu/Music/Collections/randomPicks/ipod%20on%20sep%2009/Coldplay-Sparks.mp3")

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