我在代码中添加了10个函数,甚至没有调用任何函数,但是代码停止工作! [英] I add 10 functions to a code, I don't even call any of them, but the code stops working!
本文介绍了我在代码中添加了10个函数,甚至没有调用任何函数,但是代码停止工作!的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
单独运行,此代码有效:
Alone, this code works:
CustomButton = {
1: function () {
alert("Just testing")
},
}
我添加了下面的代码,上面的代码停止工作:
I add the code below and the code above stops working:
function getvisitingnow() {
return document.location;
}
function getcontents(uri) {
var req = new XMLHttpRequest();
req.open('GET', uri, true);
req.onreadystatechange = function (aEvt) {
if (req.readyState == 4) {
if(req.status == 200) {
return req.responseText;
}
}
};
req.send();
}
function regexforsitefound(uri, searchcontents) {
var re = new RegExp("\\<div class=g\\>.*?(?:\\<a href=\\\"?(.*?)\\\"?\\>.*?){2}\\</div\\>", "mi");
var sitefound = searchcontents.match(re);
if (sitefound[0]) return sitefound[0] else return null;
}
function regexforcategoryfound(uri, searchcontents) {
var re = new RegExp("\\<div class=g\\>.*?(?:\\<a href=\\\"?(.*?)\\\"?\\>.*?){2}\\</div\\>", "mi");
var categoryfound = searchcontents.match(re);
if (categoryfound[1]) return categoryfound[1] else return null;
}
function regexfordomainname(uri) {
var re = new RegExp("http://(?:[A-Za-z0-9-]+\\.)?[A-Za-z0-9-]+\\.[A-Za-z0-9-]+/?", "si");
var domainname = uri.match(re);
if (domainname) return domainname;
}
function regexforparentdir(uri) {
var re = new RegExp("http://(?:[A-Za-z0-9-]+\\.)?[A-Za-z0-9-]+\\.[A-Za-z0-9-]+/?", "si");
var parentdir = uri.match(re);
if (parentdir) return parentdir;
}
function getcomparisonlink(visitingnow) {
var searchuri = null;
var searchcontents = null;
var uri = visitingnow;
while(true) {
searchuri = 'http://www.google.com.br/search?';
searchuri += 'q='+ uri +'&btnG=Search+Directory&hl=en&cat=gwd%2FTop';
searchcontents = getcontents(searchuri);
var sitefound = regexforsitefound(searchcontents);
if (sitefound) {
var categoryfound = regexforcategoryfound(searchcontents);
if (categoryfound) {
return categoryfound;
}
} else {
var domainname = regexfordomainname(uri);
if (!domainname) {
var parentdir = regexforparentdir(uri);
uri = parentdir;
} else {
return null;
}
}
}
}
function clickedlink(event){
var visitingnow = getvisitingnow();
if (visitingnow) {
getcomparisonlink(visitingnow);
if (comparisonlink) {
tab.open(comparisonlink);
};
}
}
function createBookmarkItem() {
const XUL_NS = "http://www.mozilla.org/keymaster/gatekeeper/there.is.only.xul";
var item = document.createElementNS(XUL_NS, "toolbarbutton");
item.setAttribute("id", "Testing-Doit-Button2");
item.setAttribute("class", "bookmark-item pagerank");
item.setAttribute("tooltiptext", "Do it!");
item.setAttribute("oncommand", "testing_doit();");
return item;
}
function placeBookmarkItem() {
var toolbar = document.getElementById("PersonalToolbar");
var button = createBookmarkItem();
toolbar.appendChild(button);
}
为什么?
推荐答案
if (sitefound[0]) return sitefound[0] else return null;
此语法无效.
尝试:
if (sitefound[0])
return sitefound[0];
else
return null;
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