Flask URL路由:将多个URL路由到同一功能 [英] Flask URL Route: Route Several URLs to the same function

问题描述

我正在使用Flask 0.9.

I am working with Flask 0.9.

现在我想将三个URL路由到相同的功能:

Now I want to route three urls to the same function:

/item/<int:appitemid>
/item/<int:appitemid>/ 
/item/<int:appitemid>/<anything can be here>

<anything can be here>部分将永远不会在函数中使用.

The <anything can be here> part will never be used in the function.

我必须复制相同的函数两次才能实现此目标:

I have to copy the same function twice to achieve this goal:

@app.route('/item/<int:appitemid>/')
def show_item(appitemid):

@app.route('/item/<int:appitemid>/<path:anythingcanbehere>')
def show_item(appitemid, anythingcanbehere):

会有更好的解决方案吗?

Will there be a better solution?

推荐答案

为什么不只使用默认值为None的可能为空的参数?

Why not just use a parameter that can potentially be empty, with a default value of None?

@app.route('/item/<int:appitemid>/')
@app.route('/item/<int:appitemid>/<path:anythingcanbehere>')
def show_item(appitemid, anythingcanbehere=None):

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