如何扁平化嵌套元组? [英] How to flatten a nested tuple?
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问题描述
我有一个嵌套的元组结构，如(String,(String,Double))，我想将其转换为(String,String,Double).我有各种各样的嵌套元组，并且我不想手动转换每个元组.有什么方便的方法吗?
I have a nested tuple structure like (String,(String,Double)) and I want to transform it to (String,String,Double). I have various kinds of nested tuple, and I don't want to transform each manually. Is there any convenient way to do that?
推荐答案
如果使用不变形，<一个href ="https://github.com/milessabin/shapeless/blob/master/examples/src/main/scala/shapeless/examples/flatten.scala" rel ="noreferrer">这正是我认为您需要.
If you use shapeless, this is exactly what you need, I think.
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