指数位数 [英] Number of digits in exponent
本文介绍了指数位数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
是否可以设置用于打印浮点数指数的位数?我想将其设置为3.
Is it possible to set the number of digits to be used for printing the exponent of a floating-point number? I want to set it to 3.
当前
f = 0.0000870927939438012
>>> "%.14e"%f
'8.70927939438012e-05'
>>> "%0.14e"%f
'8.709279e-005'
我要打印的是:
'8.70927939438012e-005'
推荐答案
没有办法控制它,最好的方法就是为此编写一个函数.
There is a no way to control that, best way is to write a function for this e.g.
def eformat(f, prec, exp_digits):
s = "%.*e"%(prec, f)
mantissa, exp = s.split('e')
# add 1 to digits as 1 is taken by sign +/-
return "%se%+0*d"%(mantissa, exp_digits+1, int(exp))
print eformat(0.0000870927939438012, 14, 3)
print eformat(1.0000870927939438012e5, 14, 3)
print eformat(1.1e123, 4, 4)
print eformat(1.1e-123, 4, 4)
输出:
8.70927939438012e-005
1.00008709279394e+005
1.1000e+0123
1.1000e-0123
这篇关于指数位数的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文