我如何使浮点数仅显示一定数量的小数 [英] How do I make a float only show a certain amount of decimals

问题描述

我有一个浮点数，该浮点数具有16个小数位，但是我希望将其限制为6，如果我得到的浮点数小于6个小数，我希望它加0直到它具有6. 即:

I have a float that has 16 decimal places, but I want it to be capped at 6, and if I ever get a float that has less than 6 decimals, I want it to add 0s until it has 6. i.e.:

1.95384240549 = 1.953842 3.12 = 3.120000

1.95384240549 = 1.953842 3.12 = 3.120000

我正在尝试根据对象的特定需求量生成一个值.谢谢！

I'm trying to generate a value based on a certain amount of demand an object has. Thanks!

推荐答案

要舍入到小数位数，可以使用round()

To round to a certain amount of decimals you can use round()

round(1.95384240549,6) > 1.953842

对于小数点后的更多0，可以使用format():

And for more 0's after the decimal place you can use format():

format(3.12, '.6f') > '3.120000'

请注意，这是字符串类型

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