如何在Swift中的for循环中跳过索引 [英] How to skip an index in a for loop in Swift

问题描述

我正在尝试在随机条件下跳过，如果为true，则将跳过循环，但结果是打印所有元素0,1,2,3,4 我知道在Java中如果索引增加，索引将跳过，但是Swift不会发生这种情况.

更新:这是我编写的某些程序的简化版本，print()必须在每个循环后立即发生，并且索引仅在某些未知条件下才递增，我希望它的行为类似于JAVA.

for var index in 0..<5 {
  print(index)//this prints 0,1,2,3,4, this must happen right after for loop
  if some unknown condition {
      index+=1
  }
}

解决方案

索引在循环中自动递增，您可以使用where子句跳过索引:

for index in 0..<5 where index != 2 {
    print(index)
}

I'm trying to skip in a random condition that if true, will skip a loop, but results are printing all elements 0,1,2,3,4 I know in Java if index is incremented index will skip, but this is not happening Swift.?

Update: this is a simplified version of some program I wrote, the print() has to be happen right after each loop, and index is ONLY incremented in some unknown conditions, I want it to behave like JAVA.

for var index in 0..<5 {
  print(index)//this prints 0,1,2,3,4, this must happen right after for loop
  if some unknown condition {
      index+=1
  }
}

解决方案

The index is automatically incremented in the loop, you can skip an index with a where clause:

for index in 0..<5 where index != 2 {
    print(index)
}

这篇关于如何在Swift中的for循环中跳过索引的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！