打印矩形-我需要其他打印，但无法正常工作 [英] Printing a rectangle - I want an additional print but I can't get it work
问题描述
我自己做了一个任务，以学习Java编程，特别是关于打印.
Made an own task for me to learn programming in java, about printing in particular.
例如，我们输入了8.然后，我们必须获得由"+"制成的矩形作为输出，因此看起来像这样:
As example, we have input 8. Then we must get as output a rectangle made of "+", so it would look like this:
++++++++
+ +
+ +
+ +
+ +
+ +
+ +
+ +
++++++++
以下代码将执行此操作(如果您想让我解释一下，请告诉我，我会执行此操作):
The following code will do this (if you want me to explain it, please tell me and I will do it):
public class Printest{
public static void main(String[] args){
int x = Integer.parseInt(args[0]);
for(int i=0; i<x; i++){
System.out.print("+");
}
System.out.println("");
for(int i=0; i<x-1; i++){
System.out.print("+");
for(int j=0; j<x-2; j++){
System.out.print(" ");
}
System.out.print("+");
System.out.println("");
}
for(int j=0; j<x; j++){
System.out.print("+");
}
}
}
但是现在我想添加一个附加功能，以便在该正方形的内部有一个十字形，我该怎么做?我试图添加一些if语句，但是我总是最终将矩形移至左右边缘..:/
But now I want add an additional feature so there is a cross inside of this square, how can I do it? I have tried to add some if-statements but I always ended up shifting the rectangles left and right edges.. : /
我希望它看起来更精确:
I want it looks like this to be more precise:
+++++++++
+* *+
+ * * +
+ * * +
+ * +
+ * * +
+ * * +
+* *+
+++++++++
您将如何做? if语句似乎不起作用，并且我觉得由于多个单独的for循环，无法在我的代码中实现它..
How would you do it? if-statements doesn't seem to work and I have the feeling it's not possible to implement this in my code because of the multiple, separate for-loops..?
顺便说一句，也许有更简单的方法来完成这项工作(只需打印矩形)?我认为我采取了一种非常复杂且效率低下的方式.如果它们不是更复杂的话，我会很想知道更简单的方法:P
By the way, is there maybe a much easier way to get this work (just print the rectangle)? I think I took a very complicated and unefficient way. I would be very interested in knowing easier ways, if they aren't more complicated :P
推荐答案
顺便说一句，也许有更简单的方法来完成这项工作(只需打印矩形)?我认为我采取了一种非常复杂且效率低下的方法.
By the way, is there maybe a much easier way to get this work (just print the rectangle)? I think I took a very complicated and unefficient way.
实际上是！您可以使用2个for循环来完成此操作:
Actually yes! You can do it with 2 for loops:
public class RectangleWithShapesExample {
public static void main(String[] args) {
int number = 8;
for (int i = 0; i < number; i++) {
for (int j = 0; j < number; j++) {
if (i == 0 || i == number - 1) {
System.out.print("+");
} else {
if (j == 0 || j == number - 1) {
System.out.print("+");
} else {
System.out.print(" ");
}
}
}
System.out.println("");
}
}
}
仅此一项，就打印大小为8的矩形，然后，如果您添加以下else-if语句:
That alone, prints the rectangle of size 8, then, if you add this else-if statement:
else if (i == j || i == (number - j - 1)) {
System.out.print("*");
}
上面的第一个条件告诉您的程序打印*对角线，如下所示:\(该方向)，第二个条件求值以在另一个方向(/)打印它
The first condition above tells your program to print a * diagonal like this: \ (that orientation), and the second one, evaluates it to print it in the other direction (/)
您可以打印*十字，因此，最终您的整个程序如下所示:
You can print the * cross, so, in the end your whole program looks like this:
public class RectangleWithShapesExample {
public static void main(String[] args) {
int number = 9;
for (int i = 0; i < number; i++) {
for (int j = 0; j < number; j++) {
if (i == 0 || i == number - 1) {
System.out.print("+");
} else {
if (j == 0 || j == number - 1) {
System.out.print("+");
} else if (i == j || i == (number - j - 1)) {
System.out.print("*");
} else {
System.out.print(" ");
}
}
}
System.out.println("");
}
}
}
其输出为:
++++++++
+* *+
+ * * +
+ ** +
+ ** +
+ * * +
+* *+
++++++++
有9个元素:
+++++++++
+* *+
+ * * +
+ * * +
+ * +
+ * * +
+ * * +
+* *+
+++++++++
作为建议，我建议您在变量中留一些操作符，以使代码更具可读性，并使变量更具描述性(例如，从x到number)
As a suggestion, I recommend you to space a little your operation signs from your variables to make your code a little more readable and make your variables more descriptive (x to number for example)
这篇关于打印矩形-我需要其他打印，但无法正常工作的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
