如何遍历锯齿数组中的每个元素? [英] How to iterate over each element in a jagged array?

问题描述

我有一个二维数组，所以是一个数组数组.阵列DONT的阵列具有相同的长度. 这里是一个例子:

I have one 2 dimensional array, so an array of arrays. The arrays of the arrays DONT have the same lengths. Here an example:

double[][] multi = new double[][] { 
  { 10, 20, 30, 40, 50 }, 
  { 1.1, 2.2, 3.3, 4.4 }, 
  { 1.2, 3.2 },
  { 1, 2, 3, 4, 5, 6, 7, 8, 9 } 
};

如何遍历各列? (例如:10 1.1 1.2 1)

How can I loop through the columns? (Like: 10 1.1 1.2 1)

推荐答案

您可以这样做，以遍历整个数组的方式按列:

You can do it like this to iterate the whole array column-wise:

// Get the maximum number of columns among all rows.
int maximumColumns = 0;
for (double[] row : multi) {
    if (row.length > maximumColumns) {
        maximumColumns = row.length;
    }
}

for (int column = 0; column < maximumColumns ; column++) {
    for (int row = 0; row < multi.length; row++) {
        if (column >= multi[row].length) {
            // There is no value for this column.
        } else {
            // Do stuff here with multi[row][column].
        }
    }
}

对于所有行中都存在的特定列 ，请执行以下操作:

For a specific column that exists in all rows do this:

int columnToIterate = // Your column.
for (int row = 0; row < multi.length; row++) {
    if (columnToIterate < multi[row].length) {
        // Do stuff here with multi[row][columnToIterate].
    }
}

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