使用AJAX将数据从HTML表单提交到WebMethod [英] Use AJAX to submit data from HTML form to WebMethod

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本文介绍了使用AJAX将数据从HTML表单提交到WebMethod的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

所以我要从HTML表单中获取数据,然后使用AJAX将数据发送到Web方法,然后再发送到sqlite数据库,但是我的AJAX调用失败.我搞砸了什么?我做得对吗?

So I'm taking in data from an HTML form and then using AJAX to send the data to a web method to then be sent to a sqlite database, but my AJAX call is failing. What did I mess up? Am I doing it correctly?

HTML表单

<form id="addForm" >
     <input type="text"  name="playername" id="playername" placeholder="Player"/> 
     <input type="text" name="points" id="points" placeholder="Points" />
     <input type="text" name="steals" id="steals" placeholder="Steals" />
     <input type="text" name="blocks" id="blocks" placeholder="Blocks" /> 
     <input type="text" name="assists" id="assists" placeholder="Assists" />
     <input type="text" name="mpg" id="mpg" placeholder="MPG" /> 
     <input type="text" name="shotpct" id="shotpct" placeholder="Shot %" />
     <input type="text" name="threepct" id="3pct" placeholder="3 %" /> 
     <input type="button" value="add player" id="addbtn" name="addbtn" />
     </form>

AJAX

 $("#addbtn").click(function () {
                var form = $("#addForm").serializeArray();
                $.ajax({
                    type: 'POST',
                    url: "players.aspx/addRow",
                    data: JSON.stringify(form),
                    dataType: 'json',
                    success: function () {
                        alert('success');
                    },
                    error: function () {
                        alert('failure');
                    }
                });
                    });

和网络方法(尚未完成,只是在测试以查看我是否正在获取数据)

and the web method(not finished, was just testing to see if I was getting data)

[WebMethod]
        public static void addRow(object form)
        {
            var stuff = form;
        }

我仍在学习如何使用大量此类内容,因此将不胜感激任何帮助.

I'm still learning how to use a lot of this stuff so any help will be greatly appreciated.

推荐答案

替换

type: 'POST',

使用

method: 'POST',

dataType:"json" 不需要,因为您没有收到数据.从服务器返回的数据将根据dataType参数进行格式化.

dataType: 'json' is not needed since you're not receiving data back. The data returned from the server, is formatted according to the dataType parameter.

还删除JSON.stringify(form),这已经通过.serialize()完成了;

Also remove JSON.stringify(form),this is already done with the .serialize();

这篇关于使用AJAX将数据从HTML表单提交到WebMethod的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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