如何检查Windows窗体是否已经存在，如果存在，则将其打开，如果不存在，则创建一个新窗体? [英] How to check if a windows form already exists, open it if it does, creates a new one if it doesn't?

问题描述

我基本上想要做到这一点的东西

I basically want something that does this:

if (form.isOpen() == true)
    form.ShowDialog();
else
    form f = new form();

我有一个表单，显示添加到订单中的项目的列表，但是当我转到另一个页面并导航回以生成订单表单时，它将调用form f = new form();，我相信它将重置该表单.关于如何可以克服的任何建议?

I have a form that displays a list of items added to an order, but when I go to another page and navigate back to make an order form it calls form f = new form();, which I believe resets the form. Any suggestions of how this can be overcome?

推荐答案

您可以使用Application.OpenForms属性检查打开的表单，如下所示:

You can check which forms are open using Application.OpenForms property as follows:

if (Application.OpenForms.OfType<MyForm>().Any())
{
    Application.OpenForms.OfType<MyForm>().First().BringToFront();
}
else
{
    form f = new MyForm();
    f.show();
}

这篇关于如何检查Windows窗体是否已经存在，如果存在，则将其打开，如果不存在，则创建一个新窗体?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！