如何通过PHP从HTML表单输出复选框? [英] How to output checkboxes from an HTML form by PHP?

问题描述

我的HTML表单为:

<form action="something.php" method="POST" enctype="multipart/form-data" id="color">
<fieldset>
    <legend><h2><span style="color: #993300; text-shadow: #808080 2px 1px 2px; font-size: 25px;">Color Preferences:</span></h2></legend>&nbsp;
    <p><table>
        <tbody>
            <tr>
                <td width="350px;"><span style="color: #993300;">*</span> Colors you consider to use to your new Site:</td>
                <td>
                                  <br/> 
                                  <input type="checkbox" name="color[]" value="Black" /> Black<br/> 
                                  <input type="checkbox" name="color[]" value="Blue" /> Blue<br/> 
                                  <input type="checkbox" name="color[]" value="Brown" /> Brown<br/> 
                                  <input type="checkbox" name="color[]" value="Gray" /> Gray<br/> 
                                  <input type="checkbox" name="color[]" value="Green" /> Green<br/> 
                </td>
            </tr>
        </tbody>
    </table></p>
</fieldset>
<input type="submit" name="submit" value="Submit" /> <input type="reset" name="reset" value="Reset" />

要执行颜色表单，我使用了PHP:

$color = $_POST['color'];    
if (!isset($color))
       {
        unset($_GET['do']);
         $message = "Error = Colors are required. Please try again.";
         break;
         } else {
         $N = count($color);
         for($i=0; $i < $N; $i++){
         echo($color[$i] . " ");
         }
       }

但是当我在输出区域上测试我的代码时，结果只给出一个数组". 您能帮我解决此代码吗? (我需要将选定的颜色作为输出而不是数组".)

But when I test my code over the output area it only giving an "Array" as a result. Can you please help me to fix this code? (I need to get the selected colors as an output instead of "Array".)

我什至将代码更改为:

$color = $_POST['color'] && $_POST['color'] = array ('Black','Blue','Brown','Gray','Green','Orange','Pink','Purple','Red','Silver','Tan','White','Yellow','Dark','Light');
            if (!isset($_POST['color'])) 
            {
                unset($_GET['do']);
                echo "Error = Colors are required. Please try again.";
            } else {
                $n = count($_POST['color']);
                echo("You selected $n color(s): ");
                for($i=0; $i < $n; $i++)
                {
                    echo($_POST['color'][$i] . " ");
                }
            }

，但结果仍然只是数组"，而不是颜色名称.您能帮我解决这个问题吗?

but still the result outcome is only "Array" instead of colors name. can you please help me to resolve this issue?

我什至将代码更改为:

$color = $_POST['color'] && $_POST['color'] = array ('Black','Blue','Brown','Gray','Green','Orange','Pink','Purple','Red','Silver','Tan','White','Yellow','Dark','Light');
            if (!isset($_POST['color'])) 
            {
                unset($_GET['do']);
                echo "Error = Colors are required. Please try again.";
            } else {
                $n = count($_POST['color']);
                echo("You selected $n color(s): ");
                for($i=0; $i < $n; $i++)
                {
                    echo($_POST['color'][$i] . " ");
                }
            }

，但结果仍然只是数组"，而不是颜色名称.您能帮我解决这个问题吗?

but still the result outcome is only "Array" instead of colors name. can you please help me to resolve this issue?

推荐答案

具有color []，您将收到一个数组($ _POST ['color']).您可以测试它是isset()还是为空()

with color[], you will receive an array ($_POST['color']). You can test if it is isset() or it is empty()

如果它不为空，那么您可以像这样遍历实例的值:

if it is NOT empty, then you can iterate over the values for instance like this:

$n = count($_POST['color']);
echo("You selected $n color(s): ");
for($i=0; $i < $n; $i++)
{
  echo($_POST['color'][$i] . " ");
}

(未经测试.代码摘自此处: http: //www.html-form-guide.com/php-form/php-form-checkbox.html )

(untested. Code taken from here: http://www.html-form-guide.com/php-form/php-form-checkbox.html)

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