片段-如果ID不唯一，请替换容器 [英] Fragment - replace container, if id is not unique

问题描述

我有一个布局，其中有两个具有相同ID的视图.如果要查找视图，只需调用parentView1.findViewById(R.id.content)或parentView2.findViewById(R.id.content)即可获取正确的视图.

I have a layout that has two views with the same id. If I want to find the view I just call parentView1.findViewById(R.id.content) or parentView2.findViewById(R.id.content) to get the correct view.

如果我想用一个片段替换一个容器，我能以某种方式定义我想要替换的那个容器吗?

If I want to replace a container with a fragment, can I somehow define which one I want to be replaced?

推荐答案

您应将相同的id布局包装在父布局中.然后将第二个容器的ID设置为其他整数.例如，布局文件如下所示:

You should wrap the same id layouts in a parent layout. And then set the id for second container to a different integer. For example layout file would look like this:

<LinearLayout 
    xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:orientation="vertical"
    tools:context=".MainActivity">
 <LinearLayout
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:orientation="vertical"
    android:id="@+id/parent_one">

    <include layout="@layout/container" />

</LinearLayout>

<LinearLayout
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:orientation="vertical"
    android:id="@+id/parent_two">

    <include layout="@layout/container"/>

</LinearLayout>
</LinearLayout>

您将首先通过使用父ID来访问它们.然后将第二个容器的ID设置为其他容器.例如:

And you would access them from using parent ids first. Then setting the id for second container to a different one. For example:

    val containerOneId = parent_one.container.id
    val containerTwoId = 1
    parent_two.container.id = containerTwoId

    openFragment(TestFragment().apply {
        val b = Bundle()
        b.putString(TestFragment.ARG, "Fragment one")
        arguments = b
    }, containerOneId)

    openFragment(TestFragment().apply {
        val b = Bundle()
        b.putString(TestFragment.ARG, "Fragment two")
        arguments = b
    }, containerTwoId)

使用相同的访问逻辑，但是使用Java(以防您未使用Kotlin)

Same access logic but in Java (in case you're not using Kotlin)

    LinearLayout parentOne = (LinearLayout) findViewById(R.id.parent_one);
    LinearLayout parentTwo = (LinearLayout) findViewById(R.id.parent_two); 

    FrameLayout containerOne = parentOne.findViewById(R.id.container);
    FrameLayout containerTwo = parentTwo.findViewById(R.id.container);

    int containerOneId = containerOne.getId();
    int containerTwoId = 1;
    containerTwo.setId(containerTwoId);

    openFragment(new TestFragment(), containerOneId);
    openFragment(new TestFragment(), containerTwoId);

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