将成员信息反射到Func< T1，T2>. [英] Reflection MemberInfo to Func<T1, T2>

问题描述

我正在寻找一种将MemberInfo实例转换为"Func"类型的方法(以便稍后通过lambda表达式使用).

I'm looking for a method to convert instance of MemberInfo to "Func" type (to use it through lambda expression later).

说，我有一个类型为成员的成员函数

Lets, say I have a member function of type

public bool func(int);

使用反射，我以某种方式获取了MemberInfo"mi"的实例，现在我想将其转换为Func<int, bool>;类型.像这样:

Using reflection, I somehow get instance of MemberInfo "mi", now i want to convert it to Func<int, bool>; type. something like:

Func<int, bool f = myType.GetMember(mi.Name);

有办法吗?

ps.马克·格雷威尔(Marc Grawell)的答案解决了我的问题，无需进一步评论

ps. Marc Grawell's answer resolves my issue, no need for further comments

推荐答案

Func<int,bool> f = Delegate.CreateDelegate(
           typeof(Func<int,bool>), target, (MethodInfo)mi);

请注意，由于func是非static方法，因此target是您要使用的 object .如果它是static方法，则可以忽略(或传递null).另外，如果将其设为Func<Foo, int, bool>，其中Foo是声明func的类型，则可以省略target(或传递null).

Note here that target is the object you want to use, since func is a non-static method. If it was a static method, you can omit that (or pass null). Alternatively, you can omit target (or pass null) if you make it a Func<Foo, int, bool> where Foo is the type that declares func.

但是！！！注意，在创建lambda表达式方面，具有Func<int,bool>在很大程度上没有意义； lambda表达式很少使用委托.

However!!! Note that having a Func<int,bool> is largely meaningless in terms of creating a lambda expression; lambda expressions rarely use delegates.

这篇关于将成员信息反射到Func< T1，T2>.的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！