PHP函数检查违禁单词 [英] PHP function to check for banned words

问题描述

我具有此功能来检查字符串中是否有禁止的单词.但是，如果删除空格，我将无法检测到禁用词-导致该功能无用.有人可以帮助我改进它来检测没有空格的单词.

I have this function to check for banned words in my string. However, I cannot detect banned words if the spaces are removed - rendering the function useless. Can someone help me improve it to detect the words without spaces.

$string = "Hellomynameisuser.";
check_for_banned_words($string);

function check_for_banned_words($string){
    $badWords = array(
        "ban",
        "bad",
        "user",
        "pass",
        "stack",
        "name",
        "html"
    );
    $matches = array();
    $matchFound = preg_match_all(
        "/\b(" . implode($badWords,"|") . ")\b/i", 
        $string, 
        $matches
    );
    if($matchFound):
        $words = array_unique($matches[0]);
        echo("<ul>");
        foreach($words as $word):
            echo("<li>" . $word . "</li>");
        endforeach;
        echo("</ul>");
    endif;
}

推荐答案

\b检测到单词边界，将其删除以得到常规匹配.

\b detects word boundaries, remove them to get a regular match.

"/(" . implode("|", $badWords) . ")/i", 

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