变量值的swap()函数 [英] swap() function for variables's values

问题描述

对于下面的交换函数，我无法获得所需的结果，在这里我希望将值打印为3,2

I am not able to achieve the desired result for this swap function below, where I want the values printed as 3,2

function swap(x,y){
 var t = x;
 x = y;
 y = t;
}

console.log(swap(2,3));

任何线索将不胜感激！

推荐答案

您的函数在内部交换值，但该函数不返回值.

Your function is swapping the values internally, but the function does not return a value.

以下方法以与提供的相反的顺序返回值的数组.

The following method returns an array of values in reverse order of what was supplied.

function swap(x, y) {
    var t = x;
    x = y;
    y = t;
    return [x, y];
}

console.log(swap(2, 3));

但是，您可以轻松地执行以下代码段的操作，因为-根据您提供的代码-似乎不需要实际交换参数的值.

However, you could easily do something like the following snippet, because - based on your supplied code - there seems to be no need to actually swap the values of the arguments.

function swap(x, y) {
    return [y, x];
}

console.log(swap(2, 3));

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