如何设置通过参数传递给函数的int值并将其分配给全局,以便我可以在函数外部使用? [英] how to set a int value passed by parameter to a function and assign it to global so I can use outside of the function?
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问题描述
如何设置通过参数传递给函数的int值并将其分配给全局值,以便可以在函数外部使用?
示例:
int assignValues(int valor_assign1, valor_assign2){
valor_assign1 = 7;
valor_assign2 = 3;
}
main (){
int valor1 = 0;
int valor2 = 0;
assignValues(valor1,valor2);
printf("%d,%d",valor1, valor2);
}
输出实际上是0,0,我希望它是7,3,我该怎么做? 我知道这是一个简单的问题,但我一直在尝试和搜索,但找不到类似的内容=/ 提前致谢.
解决方案
您可以将指向整数的指针传递给函数,而不是传递值.例如:
int assignValues(int *valor_assign1, int *valor_assign2){
*valor_assign1 = 7;
*valor_assign2 = 3;
}
main (){
int valor1 = 0;
int valor2 = 0;
assignValues(&valor1, &valor2);
printf("%d,%d",valor1, valor2);
}
但是,您可能想阅读指针教程.>
how to set a int value passed by parameter to a function and assign it to global so I can use outside of the function?
Example:
int assignValues(int valor_assign1, valor_assign2){
valor_assign1 = 7;
valor_assign2 = 3;
}
main (){
int valor1 = 0;
int valor2 = 0;
assignValues(valor1,valor2);
printf("%d,%d",valor1, valor2);
}
The output is actually 0,0 I want it to be 7,3 how do I do this? I know its a simple question but I've been trying and searching but I can't find anything like that =/ Thanks in advance.
解决方案
You could pass a pointer to your integers into the function, instead of passing the values. E.g.:
int assignValues(int *valor_assign1, int *valor_assign2){
*valor_assign1 = 7;
*valor_assign2 = 3;
}
main (){
int valor1 = 0;
int valor2 = 0;
assignValues(&valor1, &valor2);
printf("%d,%d",valor1, valor2);
}
You might want to read a pointer tutorial, however.
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