运行超过x分钟的进程的Grep计数 [英] Grep count of processes running more than x minutes

问题描述

我的目标是在bash中使用grep记录比"x"分钟还早的进程.

My goal is to grep for a count of processes older than 'x' minutes in bash.

到目前为止，我可以对所有进程执行时间进行grep设置:

So far, I can grep for all the process execution times:

ps -eo etime,cmd | grep mysuperspecialprocess.sh | grep -Ev 'grep' | awk '{print $1}'

我用管道输送wc -l在末尾计数.

I pipe a wc -l to get a count at the end.

如何对结果进行grep或循环遍历以将其限制为超过一定分钟数的进程?

How can I grep or loop through the result to restrict it to processes older than a certain number of minutes?

推荐答案

尝试通过此测试版本.

Give this tested version a try.

它将搜索指定的运行进程，并计算所有关联事件的经过时间大于指定秒数的事件.

It searches a specified running process, and count all occurences which has an associated elapsed time greater than a specified number of seconds.

首先设置参数的值并运行它.

Set parameters' values first and run it.

$ cat ./script.sh 
#!/bin/bash --

process_name=mysuperspecialprocess.sh

elapsed_time_seconds=600

ps -eo etimes,cmd | fgrep "${process_name}" | fgrep -v fgrep | ( count=0 ; while read etimes cmd ; do \
  if [ $etimes -gt $elapsed_time_seconds ] ;\
  then \
    count=$((count+1)) ;\
  fi ;\
done ; echo $count )

倍次数指示 ps 显示秒数.

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