仅模式匹配字符串 [英] Only pattern matching string

问题描述

我有一个包含单词

abciuf.com abdbhj.co.in abcshjkl.org.in.2 abciuf zasdg cbhjk asjk 

，包括其他内容.以abci, abdb, abcs, abai开头的单词是我的要求.因此，我只希望打印以abci, abdb, abcs, abai开头的单词，例如-abciuf.com abdbhj.co.in abcshjkl.org.in.2 abciuf Azerbaijan

including other contents. The word starts with abci, abdb, abcs, abai is my requirement. So I want only the word which print starts with abci, abdb, abcs, abai like - abciuf.com abdbhj.co.in abcshjkl.org.in.2 abciuf Azerbaijan

我已经通过grep命令尝试过，但是对我没有帮助

I have tried via grep command but it doesn't help me

cat /etc/xyz.txt|egrep -o "abdb*|abci*|abcs*|abai*"
cat /etc/xyz.txt|egrep -Eow "abdb*|abci*|abcs*|abai*"

推荐答案

您也可以尝试Perl

You can try Perl also

 perl -ne ' while(/(\b(abdb|abci|abcs|abai)\S+)/g) { print "$1 \n" } '

使用您的输入

$ cat sin15.txt
abciuf.com abdbhj.co.in abcshjkl.org.in.2 abciuf zasdg cbhjk asjk

$ perl -ne ' while(/(\b(abdb|abci|abcs|abai)\S+)/g) { print "$1 \n" } ' sin15.txt
abciuf.com
abdbhj.co.in
abcshjkl.org.in.2
abciuf

$

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