如何找到特定字符串的正则表达式 [英] how to find a regular expression of specific string

问题描述

我有一个与正则表达式有关的问题.我有一个巨大的文本文件，例如

I have a question related to a regular expression. I have a huge text file like

我想要得到这样的输出

 ID           DE
1.1      Transformer
1.12     Best bye
1.1.1    Iphone

所以基本上我想获得ID和DE

so basically I want to get ID and DE

我尝试过使用awk和sed，但没有成功.我以为我先得到ID，然后再得到DE，然后合并它们，但是我仍然不知道该怎么做

what I tried was using awk and sed but with no success. I thought I get the ID and then I get the DE and then I merge them but I still could not figure out how to do that

sed -n ID my.txt

sed -n ID my.txt

我使用了 -n ，因为默认情况下，在所有命令都应用到标准输出后，每一行都会回显到标准输出.

I used -n because By default, each line of input is echoed to the standard output after all of the commands have been applied to it.

推荐答案

如OP所述，如果任何de为空且相应的id为空，则打印连字符，然后尝试执行以下操作.

As OP mentioned in case any de is empty with respective id then print an hyphen, then try following.

awk '
BEGIN{
  OFS="\t"
  print "ID\t\tDE"
}
/ID/{
  if(id){
    print id,de?de:"-"
    id=de=""
  }
  id=$2
  next
}
/DE/{
  $1=""
  sub(/^ +/,"")
  de=$0
}
END{
  if(id){
    print id,de?de:"-"
  }
}'  Input_file

---

---

请您试一下.

---

---

Could you please try following.

awk '
BEGIN{
  OFS="\t"
  print "ID\t\tDE"
}
/ID/{
  if(id){
    print id,de
    id=de=""
  }
  id=$2
  next
}
/DE/{
  $1=""
  sub(/^ +/,"")
  de=$0
}
END{
  if(id){
    print id,de
  }
}'   Input_file

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