awk或sed单独提取每个列数 [英] awk or sed extract each number of column alone

问题描述

您好，我想通过命令将每个行数提取到文件中.

Hello i want to extract each line count to a file by command.

4495125 94307025    [e-mail]   94307025.094307025  12443
stazla  [e-mail]  1992/.:\1
1447585 [e-mail] h1st@1
saknit  [e-mail]   1233    1990
_______________________________________________________
5column.txt
4495125 94307025    [e-mail]   94307025.094307025  12443
_______________________________________________________
4column.txt 
saknit  [e-mail]   1233    1990
_______________________________________________________
3column.txt 
stazla  [e-mail]  1992/.:\1
1447585 [e-mail] h1st@1

我需要代码来完成这项工作！！

i need code to do this job please!!

推荐答案

跟随awk可以帮助您.

awk '{print > NF"column.txt"}'  Input_file

输出它将创建3个名为5column.txt，4column.txt和3column.txt的文件.

Output it will create 3 files named 5column.txt, 4column.txt and 3column.txt.

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