如何打印uint32_t和uint16_t变量值? [英] How do I print uint32_t and uint16_t variables value?

问题描述

我正在尝试打印uint16_t和uint32_t值，但是它没有提供所需的输出.

I am trying to print an uint16_t and uint32_t value, but it is not giving desired output.

#include <stdio.h>
#include <netinet/in.h>

int main()
{
     uint32_t a=12,a1;
     uint16_t b=1,b1;
     a1=htonl(a);
     printf("%d---------%d",a1);
     b1=htons(b);
     printf("\n%d-----%d",b,b1);
     return 0;
}

我也用过

 printf("%"PRIu32, a);

显示错误.

如何打印这些值以及所需的输出是什么?

How do I print these values and what will be the desired output?

推荐答案

如果您要为intN_t类型及其兄弟创建所有漂亮的新格式说明符，并且为正确的(即可移植的)方法，前提是您的编译器符合C99.如果大小与您的想法不同，则不应使用%d或%u之类的标准字体.

You need to include inttypes.h if you want all those nifty new format specifiers for the intN_t types and their brethren, and that is the correct (ie, portable) way to do it, provided your compiler complies with C99. You shouldn't use the standard ones like %d or %u in case the sizes are different to what you think.

它包括stdint.h，并用很多其他东西扩展了它，例如可以用于printf/scanf调用族的宏. ISO C99标准的7.8节对此进行了介绍.

It includes stdint.h and extends it with quite a few other things, such as the macros that can be used for the printf/scanf family of calls. This is covered in section 7.8 of the ISO C99 standard.

例如，以下程序:

#include <stdio.h>
#include <inttypes.h>
int main (void) {
    uint32_t a=1234;
    uint16_t b=5678;
    printf("%" PRIu32 "\n",a);
    printf("%" PRIu16 "\n",b);
    return 0;
}

输出:

1234
5678

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