传递指向成员函数的指针在MinGW-w64中进行编译，但在gcc中不进行编译 [英] Pass pointer to member function compiles in MinGW-w64 but not in gcc

问题描述

我有一个Worker对象，该对象带有run()个非静态成员函数.

I have a Worker object with a run() non static member function.

已创建一个对象:

Worker * worker = new Worker();

正在做

std::thread(Worker::run, worker);

在MinGW-w64(gcc 4.9.1)下但在来自Ubuntu的linux(gcc 5.2.1)下编译(一种工程)，我得到了编译错误:

Compiles (an works) under MinGW-w64 (gcc 4.9.1) but under linux (gcc 5.2.1) from Ubuntu, I get the compilation error:

Invalid use of non-static member function

代码是使用-std=gnu++11

我知道在MinGW情况下，指向成员函数的指针具有带有Worker * this参数类型的签名，从而可以像静态函数指针一样使用它.为什么在Linux 5.2.1 gcc中禁止这样做，我应该怎么写?

I understand that in the MinGW case, the pointer to the member function has a signature with a kind of Worker * this parameter, allowing to use it like a static function pointer. Why is this forbidden in the linux 5.2.1 gcc, and how should I write that?

编辑:我可以使用lambda或在Worker::run之前添加&来解决此问题，但是各种gcc版本为何接受还是不接受这一问题.这是MinGW还是gcc 4.9.1错误?

EDIT : I can solve this using a lambda or by adding & before Worker::run, but the question why it is accepted or not by various gcc versions remains. Is this a MinGW or gcc 4.9.1 bug?

推荐答案

您需要使用

std::thread(&Worker::run, worker);

在线示例

live example

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