使用插入式火车的二项式GLM [英] Binomial GLM using caret train

问题描述

我想在某个数据集上拟合二项式GLM.使用glm(...，family = binomial)一切正常，但是我想使用插入符号train()函数来完成.不幸的是，我遇到了无法消除的意外错误.

I would like to fit a Binomial GLM on a certain dataset. Using glm(...,family=binomial) everything works fine however I would like to do it with the caret train() function. Unfortunately I get an unexpected error which I cannot get rid of.

library("marginalmodelplots")
library("caret")

MissUSA <- MissAmerica08[,c(2,4,6,7,8,10)]
formula <- cbind(Top10, 9-Top10)~.
glmfit <- glm(formula=formula, data=MissUSA, family=binomial())

trainfit <-train(form=formula,data=MissUSA,trControl=trainControl(method = "none"),   method="glm", family=binomial()) 

我得到的错误是:

错误:nrow(x)==长度(y)不正确"

"Error : nrow(x) == length(y) is not TRUE"

推荐答案

caret不支持用于二项式结果的分组数据.您可以将数据扩展为二进制(伯努利)数据的因子变量.另外，如果执行此操作，则无需在对train的调用中使用family=binomial().

caret doesn't support grouped data for a binomial outcome. You can expand the data into a factor variable that is binary (Bernoulli) data. Also, if you do that, you do not need to use family=binomial() in the call to train.

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