从全局表达式创建正则表达式 [英] Create regex from glob expression

问题描述

我编写了使用正则表达式解析文本的程序.正则表达式应从用户那里获取.我不愿意使用glob语法进行用户输入，并在内部将glob字符串转换为正则表达式.例如:

i write program that parse text with regular expression. Regular expression should be obtained from user. I deside to use glob syntax for user input, and convert glob string to the regular expression internally. For example:

"foo.? bar*" 

应转换为

"^.*foo\.\w\bar\w+.*"

以某种方式，我需要从字符串中转义所有有意义的字符，然后我需要替换glob *和?带有正则表达式语法的字符.最方便的方法是什么?

Somehow, i need to escape all meaningful characters from the string, then i need to replace glob * and ? characters with apropriate regexp syntax. What is the most convinient way to do this?

推荐答案

不需要不完整或不可靠的黑客手段. python包含了一个为此功能的功能

no need for incomplete or unreliable hacks. there's a function included with python for this

>>> import fnmatch
>>> fnmatch.translate( '*.foo' )
'.*\\.foo$'
>>> fnmatch.translate( '[a-z]*.txt' )
'[a-z].*\\.txt$'

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