glsl无限常数 [英] glsl infinity constant

问题描述

GLSL是否具有用于+/- infinity或NaN的任何预定义常数?我正在作为一种解决方法，但是我想知道是否有一种更清洁的方法:

Does GLSL have any pre-defined constants for +/-infinity or NaN? I'm doing this as a workaround but I wonder if there is a cleaner way:

// GLSL FRAGMENT SHADER
#version 410

<snip>

const float infinity = 1. / 0.;

void main ()
{
    <snip>
}

我知道isinf函数，但是我需要为变量分配无穷大，以至于无济于事.

I am aware of the isinf function but I need to assign infinity to a variable so that does not help me.

推荐答案

就像 Nicol 所述，没有预定义的常量.

Like Nicol mentioned, there are no pre-defined constants.

但是，从OpenGL 4.1开始，至少可以保证您的解决方案能够正常工作并正确生成一个无限值.

However, from OpenGL 4.1 on, your solution is at least guaranteed to work and correctly generate an infinite value.

例如参见 glsl 4.4 :

4.7.1范围和精度

...

但是，将非零除以0会导致 正确签名的IEEE Inf :如果同时实现了正零和负零，则正确签名 将生成Inf，否则将生成正Inf.

However, dividing a non-zero by 0 results in the appropriately signed IEEE Inf: If both positive and negative zeros are implemented, the correctly signed Inf will be generated, otherwise positive Inf is generated.

不过，在使用旧版OpenGL时要小心:

Be careful when you use an older version of OpenGL though:

例如，在 glsl 4.0 中，它说:

4.1.4浮动

...

类似地，处理诸如除以0之类的条件可能会导致不确定的结果，但在任何情况下都不应导致中断或终止处理.

Similarly, treatment of conditions such as divide by 0 may lead to an unspecified result, but in no case should such a condition lead to the interruption or termination of processing.

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