使用pointinterval减少点数 [英] Using pointinterval to reduce the number of points

问题描述

使用pointinterval，可以告诉Gnuplot何时在线上插入点.现在，通过将其设置为-1，该行不会越过该点.例如

With pointinterval, it is possible to tell Gnuplot when to insert the point on the line. Now, by setting that to -1, the line doesn't go though the point. For example

pi -1

----<>----<>----<>----<>----<>----<>----<>----<>----<>----

pi 2

----<->----------<->----------<->----------<->----------<->----

如您所见，使用-1以外的值会将线插入点内.

As you can see, using values other than -1 will insert the line inside the point.

我想使用正数pi来减少可见点的数量，同时我希望看到线没有穿过该点.像这样

I want to use positive pi in order to reduce the number of visible points and at the same time I want to see that the line doesn't go through the point. Something like this

----<>----------<>----------<>----------<>----------<>----

那怎么可能?

推荐答案

只需使用较大的负数，例如pi -5:

Just use a larger, negative number like pi -5:

set xrange [0:1]
plot '+' using 1:($1**2) pi -5 pt 6 lw 2 ps 1.5 w lp t 'pi -5', \
     '+' using 1:($1**2 + 0.1) pi 5 pt 6 lw 2 ps 1.5 w lp t 'pi 5'

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