转换imageNamed到imageWithContentsOfFile： [英] Converting imageNamed to imageWithContentsOfFile:

问题描述

我的code为我的图片是

My code for my images is

-(IBAction)start:(id)sender
{
    animation.animationImages = [NSArray arrayWithObjects:
                                 [UIImage imageNamed:@"Paddle 1.png"],
                                 [UIImage imageNamed:@"Paddle 2.png"],
                                 [UIImage imageNamed:@"Paddle 3.png"],
                                 [UIImage imageNamed:@"Paddle 4.png"],
nil];
    [animation setAnimationRepeatCount:0];
    animation.animationDuration = 2.5;
    [animation startAnimating];
}

这是缓存的内存太多，我是在一个previous的问题告诉我交换code使用

This is caching too much memory and I was told in a previous question to swap my code to using

[UIImage imageWithContentsOfFile: GetImgWithoutCaching(@"Paddle 1.jpg")]

和

UIImage* GetImgWithoutCaching(NSString* imgName)
{
    NSString *imagePath = [[NSBundle mainBundle] pathForResource:imgName ofType:nil];
    return [UIImage imageWithContentsOfFile:imagePath];
}

什么是写code的正确方法？我做的地方，code在我的.m的是什么？

What is the correct way of writing the code? do i place that code in my .m as is?

推荐答案

首先，你应该检查是否采用视网膜图片：

First you should check if using retina picture:

BOOL isHighResolution = NO;
if ([[UIScreen mainScreen] respondsToSelector:@selector(scale)]) {
    if ([UIScreen mainScreen].scale > 1) {
        isHighResolution = YES;
    }
}

如果您使用的是视网膜图像，添加@ 2倍图像的名字，如：

if you are using retina picture, add @2x to image name, like this:

NSString *noExtFileName = [name stringByDeletingPathExtension];
if (isHighResolution) {
    if (![noExtFileName hasSuffix:@"@2x"]) {
       noExtFileName = [noExtFileName stringByAppendingString:@"@2x"];
    }
}

 //if image only "png" type
return [[NSBundle mainBundle] pathForResource:noExtFileName ofType:@"png"];

这篇关于转换imageNamed到imageWithContentsOfFile：的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！