如何从第二天开始获取特定时间 [英] How to get specific time from next day
问题描述
我想为第二天(明天)的确切时间创建一个time.Time.现在，我想设置小时和分钟.
这是我目前使用的代码:
now := time.Now()
tomorrow := time.Date(now.Year(), now.Month(), now.Day(), 15, 0, 0, 0, time.UTC).AddDate(0,0,1)
这将为今天的Date创建一个我要查找的确切时间(小时和分钟)，然后在该Date中添加一天.这很好.
示例:
想象time.Now()是2009-11-10 23:00:00 +0000 UTC.
以下代码的结果将是:2009-11-10 15:00:00 +0000 UTC
tomorrow := time.Date(now.Year(), now.Month(), now.Day(), 15, 0, 0, 0, time.UTC)
到目前为止，我使用AddDate(0, 0, 1)添加了一天.结果就是第二天的所需时间:2009-11-11 15:00:00 +0000 UTC.
请参阅: https://play.golang.org/p/OKR9V1HN50x
问题:
有没有更短的编写代码的方法?
import "time"月份，日期，小时，分钟，秒和nsec值可能不在其范围内 通常的范围，并将在转换过程中进行标准化.为了 例如，10月32日转换为11月1日.
这更有效.它将对包time函数和方法的调用减至最少.
package main
import (
"fmt"
"time"
)
func main() {
now := time.Now()
fmt.Println(now.Round(0))
yyyy, mm, dd := now.Date()
tomorrow := time.Date(yyyy, mm, dd+1, 15, 0, 0, 0, now.Location())
fmt.Println(tomorrow)
}
输出:
2019-06-21 16:23:06.525478162 -0400 EDT
2019-06-22 15:00:00 -0400 EDT
一些基准:
BenchmarkNow-8 31197811 36.6 ns/op
BenchmarkTomorrowPeterSO-8 29852671 38.4 ns/op
BenchmarkTomorrowJens-8 9523422 124 ns/op
bench_test.go:
package main
import (
"testing"
"time"
)
func BenchmarkNow(b *testing.B) {
for N := 0; N < b.N; N++ {
now := time.Now()
_ = now
}
}
var now = time.Now()
func BenchmarkTomorrowPeterSO(b *testing.B) {
for N := 0; N < b.N; N++ {
// now := time.Now()
yyyy, mm, dd := now.Date()
tomorrow := time.Date(yyyy, mm, dd+1, 15, 0, 0, 0, now.Location())
_ = tomorrow
}
}
func BenchmarkTomorrowJens(b *testing.B) {
for N := 0; N < b.N; N++ {
// now := time.Now()
tomorrow := time.Date(now.Year(), now.Month(), now.Day(), 15, 0, 0, 0, now.Location()).AddDate(0, 0, 1)
_ = tomorrow
}
}
I want to create a time.Time for an exact point in time the following day (tomorrow). For now I would like to set the hour and minute.
This is the code I use at the moment:
now := time.Now()
tomorrow := time.Date(now.Year(), now.Month(), now.Day(), 15, 0, 0, 0, time.UTC).AddDate(0,0,1)
This will create a Date for today with the exact time (hour and minute) I am looking for and then adds one day to that Date. This works fine.
Example:
Imagine time.Now() is 2009-11-10 23:00:00 +0000 UTC.
The result of the following code would be: 2009-11-10 15:00:00 +0000 UTC
tomorrow := time.Date(now.Year(), now.Month(), now.Day(), 15, 0, 0, 0, time.UTC)
To this date I add one day using AddDate(0, 0, 1). The result is then the desired time the next day: 2009-11-11 15:00:00 +0000 UTC.
See: https://play.golang.org/p/OKR9V1HN50x
Question:
Is there a shorter way to write this code?
import "time"The month, day, hour, min, sec, and nsec values may be outside their usual ranges and will be normalized during the conversion. For example, October 32 converts to November 1.
This is more efficient. It minimizes calls to package time functions and methods.
package main
import (
"fmt"
"time"
)
func main() {
now := time.Now()
fmt.Println(now.Round(0))
yyyy, mm, dd := now.Date()
tomorrow := time.Date(yyyy, mm, dd+1, 15, 0, 0, 0, now.Location())
fmt.Println(tomorrow)
}
Output:
2019-06-21 16:23:06.525478162 -0400 EDT
2019-06-22 15:00:00 -0400 EDT
Some benchmarks:
BenchmarkNow-8 31197811 36.6 ns/op
BenchmarkTomorrowPeterSO-8 29852671 38.4 ns/op
BenchmarkTomorrowJens-8 9523422 124 ns/op
bench_test.go:
package main
import (
"testing"
"time"
)
func BenchmarkNow(b *testing.B) {
for N := 0; N < b.N; N++ {
now := time.Now()
_ = now
}
}
var now = time.Now()
func BenchmarkTomorrowPeterSO(b *testing.B) {
for N := 0; N < b.N; N++ {
// now := time.Now()
yyyy, mm, dd := now.Date()
tomorrow := time.Date(yyyy, mm, dd+1, 15, 0, 0, 0, now.Location())
_ = tomorrow
}
}
func BenchmarkTomorrowJens(b *testing.B) {
for N := 0; N < b.N; N++ {
// now := time.Now()
tomorrow := time.Date(now.Year(), now.Month(), now.Day(), 15, 0, 0, 0, now.Location()).AddDate(0, 0, 1)
_ = tomorrow
}
}
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