Golang-如何创建具有不同签名的函数片段? [英] Golang - How do you create a slice of functions with different signatures?
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问题描述
如何创建具有不同签名的函数片段?我尝试了下面的代码,但感觉有点乱.我们只是硬着头皮使用切片界面{}吗?
How do you create a slice of functions with different signatures? I tried the code below but its feels hack-ish. Do we just bite the bullet and use a slice interface{}?
package main
import (
"fmt"
)
type OneParams func(string) string
type TwoParams func(string, string) string
type ThreeParams func(string, string, string) string
func (o OneParams) Union() string {
return "Single string"
}
func (t TwoParams) Union() string {
return "Double string"
}
func (t ThreeParams) Union() string {
return "Triple string"
}
type Functions interface {
Union() string
}
func Single(str string) string {
return str
}
func Double(str1 string, str2 string) string {
return str1 + " " + str2
}
func Triple(str1 string, str2 string, str3 string) string {
return str1 + " " + str2 + " " + str3
}
func main() {
fmt.Println("Slice Of Functions Program!\n\n")
fSlice := []Functions{
OneParams(Single),
TwoParams(Double),
ThreeParams(Triple),
}
for _, value := range fSlice {
switch t := value.(type) {
case OneParams:
fmt.Printf("One: %s\n", t("one"))
case TwoParams:
fmt.Printf("Two: %s\n", t("one", "two"))
case ThreeParams:
fmt.Printf("Three: %s\n", t("one", "two", "three"))
default:
fmt.Println("Huh! What's that?")
}
}
fmt.Println("\n\n")
}
这仅仅是尝试对Golang做太多事情的一个例子吗?
Is this just a case of trying to do too much with Golang?
推荐答案
请检查它,我不知道它是否是您想要的.因为我不知道你到底想要什么.
Please check it, I don't know if it what you want. Because I don't know what are you exactly want.
package main
import (
"fmt"
"reflect"
)
func A() {
fmt.Println("A")
}
func B(A int) {
fmt.Println("B", A)
}
func C(A string, B float32) {
fmt.Println("C", A, B)
}
func main() {
f := []interface{}{A, B, C}
f[0].(func())()
f[1].(func(int))(15)
f[2].(func(string, float32))("TEST", 90)
fmt.Println("\n******* another thing ******")
for a, v := range f {
v := reflect.TypeOf(v)
fmt.Println("#######", a)
fmt.Println("num param :", v.NumIn())
for i := 0; i < v.NumIn(); i++ {
fmt.Println("param :", i, "type is ", v.In(i))
}
}
}
这里我有另一个使用反射调用的示例
Here I have another example calling using reflect
package main
import (
"fmt"
"reflect"
)
func A() {
fmt.Println("A")
}
func B(A int) {
fmt.Println("B", A)
}
func C(A string, B float32) {
fmt.Println("C", A, B)
}
func main() {
f := []interface{}{A, B, C}
f[0].(func())()
f[1].(func(int))(15)
f[2].(func(string, float32))("TEST", 90)
fmt.Println("\n******* calling with reflect ******")
for a, v := range f {
v := reflect.TypeOf(v)
//calling the function from reflect
val := reflect.ValueOf(f[a])
params := make([]reflect.Value, v.NumIn())
if v.NumIn() == 1 {
params[0] = reflect.ValueOf(1564)
} else if v.NumIn() == 2 {
params[0] = reflect.ValueOf("Test FROM reflect")
params[1] = reflect.ValueOf(float32(123456))
}
val.Call(params)
}
}
检查进入游乐场
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