参考“不是类型". -将类型存储在结构中 [英] Ref "is not a type" - storing a type in a struct
问题描述
我有一个像这样的文件:
I have a file like so:
package foo
type Handler struct {}
然后在另一个文件中,我有:
and then in another file, I have:
import (
"handlers/foo"
"handlers/bar"
"handlers/baz"
)
type AllHandlers struct {
Foo foo.Handler
Bar bar.Handler
Baz baz.Handler
}
然后在另一个我拥有的文件中:
then in another file I have:
all := routes.AllHandlers{}
foo := all.Foo{}
bar := all.Bar{}
baz := all.Baz{}
但是它给了我这个错误:
but it gives me this error:
Foo不是类型
Foo is not a type
我可能做错了很多.我想做的是将所有处理程序存储在AllHandlers结构中,但不确定如何执行该操作.
I am probably doing some egregiously wrong. What I want to do is store all handlers in the AllHandlers struct, but not sure how to do that.
我相信可以通过以下方式简化问题:
I believe the question can be simplified in this way:
func (h HuruInjection) GetInjections() struct{} {
return struct {
Foo foo.Handler
Bar bar.Handler
Baz baz.Handler
}
}
上面的
不会编译,主要是因为据我所知,您将返回类型而不是值-例如,使用Class而不是该Class的实例.我该如何编译它?
the above won't compile, essentially because you are returning a type instead of a value, as far as I can tell - for example, a Class instead of an instance of that Class. How can I get this to compile?
请参见以下示例: https://gist.github.com/ORESoftware/894438aee1d16aa9b2cb12ba25df274e
推荐答案
我解决了这个问题,诀窍是使用正确的语法.而不是这样做:
I solved this problem, the trick is to use the right syntax. Instead of doing this:
import (
"handlers/foo"
"handlers/bar"
"handlers/baz"
)
type AllHandlers struct {
Foo foo.Handler
Bar bar.Handler
Baz baz.Handler
}
我这样做了:
import (
"handlers/foo"
"handlers/bar"
"handlers/baz"
)
type Foo = foo.Handler
type Bar = bar.Handler
type Baz = baz.Handler
然后我可以导入它,并使用Foo,Bar,Baz作为类型.因此,我认为您不能在结构中对类型进行分组,但是可以使用上述语法导入/导出类型.
then I could import this, and use Foo, Bar, Baz as types. So I don't think you can group types in a struct, but you can import/export types by using the above syntax.
这篇关于参考“不是类型". -将类型存储在结构中的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!