通过注释使用Hibernate UUIDGenerator [英] Using Hibernate UUIDGenerator via annotations
问题描述
我用我的UUID如下:
@Id
@GeneratedValue(发电机=的「uuid)
@GenericGenerator(名称=的「uuid」,战略=的「uuid)
@Column(名称=的「uuid」,独特= TRUE)
私人字符串UUID;
但我得到一个智能休眠警告:
使用
org.hibernate.id.UUIDHexGenerator
不产生的IETF RFC 4122
兼容UUID值;考虑使用
org.hibernate.id.UUIDGenerator而不是
块引用>所以,我想切换到org.hibernate.id.UUIDGenerator,现在的问题是我应该怎么告诉它Hibernate的发电机。我看到一些人用它作为一个休眠的UUID - 所以这是我尝试过,但阴性结果:
@Id
@GeneratedValue(发电机=休眠的UUID)
@GenericGenerator(NAME =休眠的UUID的策略=休眠的UUID)
@Column(名称=的「uuid」,独特= TRUE)
私人字符串UUID;
解决方案应该是
UUID2
:...
@GenericGenerator(名称=的「uuid」,战略=UUID2)
...请参阅 5.1.2.2.1。各种附加发电机的。
I'm using my uuid as following:
@Id @GeneratedValue(generator = "uuid") @GenericGenerator(name = "uuid", strategy = "uuid") @Column(name = "uuid", unique = true) private String uuid;
but I'm getting a smart Hibernate warning:
Using org.hibernate.id.UUIDHexGenerator which does not generate IETF RFC 4122 compliant UUID values; consider using org.hibernate.id.UUIDGenerator instead
So i want to switch to org.hibernate.id.UUIDGenerator, now question is how should I tell it to Hibernate's generator. I saw some guys used it as a "hibernate-uuid" - so this is what I've tried, but with negative result:
@Id @GeneratedValue(generator = "hibernate-uuid") @GenericGenerator(name = "hibernate-uuid", strategy = "hibernate-uuid") @Column(name = "uuid", unique = true) private String uuid;
解决方案It should be
uuid2
:... @GenericGenerator(name = "uuid", strategy = "uuid2") ...
See 5.1.2.2.1. Various additional generators.
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