gmock-如何使用noexcept说明符模拟函数 [英] gmock - how to mock function with noexcept specifier
问题描述
我需要模拟以下功能:
virtual void fun() noexcept = 0;
是否可以使用gmock?
Is it possible using gmock ?
Gmock具有以下宏:#define GMOCK_METHOD0_(tn, constness, ct, Method, ...)
,但有一条注释:// INTERNAL IMPLEMENTATION - DON'T USE IN USER CODE!!!
而且我不知道如何使用该宏(参数tn和ct表示什么)?
Gmock has the following macro:#define GMOCK_METHOD0_(tn, constness, ct, Method, ...)
but there is a comment: // INTERNAL IMPLEMENTATION - DON'T USE IN USER CODE!!!
Moreover I don't know how to use that macro (what the parameters tn and ct means) ?
修改
以下模拟:
GMOCK_METHOD0_(, noexcept, ,fun, void());
使用gmock 1.7.0进行编译,但是当我使用gmock 1.8.1进行编译时,出现编译错误:
compiles with gmock 1.7.0 but when I compile it using gmock 1.8.1 I get the compilation errors:
main.cpp:17: error: expected identifier before ‘noexcept’
GMOCK_METHOD0_(, noexcept, ,fun, void());
^
gmock-generated-function-mockers.h:153: in definition of macro ‘GMOCK_METHOD0_’
constness ::testing::internal::Function<__VA_ARGS__>* ) const { \
^
main.cpp:17: error: expected ‘,’ or ‘...’ before ‘noexcept’
GMOCK_METHOD0_(, noexcept, ,fun, void());
^
gmock-generated-function-mockers.h:153: in definition of macro ‘GMOCK_METHOD0_’
constness ::testing::internal::Function<__VA_ARGS__>* ) const { \
^
main.cpp:-1: In member function ‘testing::internal::MockSpec<void()> MockX::gmock_fun(const testing::internal::WithoutMatchers&, int) const’:
gmock-generated-function-mockers.h:154: error: ‘AdjustConstness_noexcept’ is not a member of ‘testing::internal’
return ::testing::internal::AdjustConstness_##constness(this)-> \
^
main.cpp:17: in expansion of macro ‘GMOCK_METHOD0_’
GMOCK_METHOD0_(, noexcept, ,fun, void());
^
推荐答案
现在,从v1.10.0开始,使用新语法就可以做到这一点. 请参见更改日志和
Now this is possible since v1.10.0 with the new syntax. see change log and new syntax explanation
新语法包含一个单独的参数规范以传递限定符
The new syntax contains a separate argument specs to pass the qualifiers
class MyMock {
public:
MOCK_METHOD(ReturnType, MethodName, (Args...), (Specs...));
};
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