如何按值查询边缘属性? [英] How can I query an edge property by value?

问题描述

我使用的是OrientDB(Community-2.0.9)，它有两个顶点:Person和University，一个边缘是:isStudent.边缘isStudent的'mark'属性为float.人-是学生->大学.

I'm using OrientDB (Community-2.0.9) and have two vertices: Person and University and one edge: isStudent. The edge isStudent has the property 'mark' as float. Person --isStudent--> University.

现在，我想选择标记大于3.0的所有人员，但没有结果，但是如果我查询相等性，则会得到两个结果.

Now I want to select all persons, where the mark is greater than 3.0, but I got no results, but if I query for equality I got two results.

您有任何解决方法的想法吗?

Do you have any ideas how to solve this?

查询:

SELECT FROM PERSON WHERE out_isStudent.mark = 3.4 --> two results
SELECT FROM PERSON WHERE out_isStudent.mark > 3.0 --> no results

推荐答案

如果您:

select out_isStudent.mark from Person

您看到它返回列表 [3.4] ，而不是 3.4

you see that it returns the list [3.4] instead of 3.4

由于要比较 [3.4] == 3.4

您可以使用以下方法实现自己想要的:

You can achieve what you want with:

select from Person where out_isStudent[0].mark > 3

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