创建复杂的gremlin-java查询 [英] create complex gremlin-java query

问题描述

我在泰坦图数据库中实现了模型，其关系如下所示:

I have model implemented in titan graph database with relations presented below:

[A] ---(e1)---> [B] <---(e2)--- [C] ---(e3)---> [D]
 |      |        |       |       |      |        |
prop:id |    prop:number |       | label:e3      |
        |                |    prop:id            |
   label:e1         label:e2                 prop:number
    prop:prop1

A和B是主要顶点"(例如用户)，B和C顶点是不太重要的顶点"，用于描述与用户相关的某些数据.

A and B are "main vertices" (for example users), vertices B and C are "less important vertices" describing some data connected with users.

查询算法的输入是顶点A的属性id.

The input for the query algorithm is property id of vertex A.

我想找到所有以上述方式与A连接的顶点D.此外，我想记住A和B之间的边e1的属性prop1.

I want to find all such vertices D, that are connected with A in the manner shown above. What's more I want to remember the property prop1 of the edge e1 between A and B.

更准确地说，我想高效地检索对(prop1, numberD)，其中prop1是A -> B之间的边的属性(如果边缘具有此属性)，而numberD是number >.

More precisely, I want to efficiently retrieve pairs (prop1, numberD) where prop1 is the property of edge between A -> B (if the edge has this property), and numberD is the property number from D.

我不知道如何有效地执行此查询.

I don't know how to efficiently implement this query.

很容易只检索顶点D(使用GremlinPipes):

It is easy to retrieve only vertices D (using GremlinPipes):

pipe
.start(startVertex)
.outE("e1")
.inV().hasProperty("number")
.inE("e2")
.outV().hasProperty("id")
.outE("e3")
.inV().hasProperty("number");

但是当我还需要获得边缘e1并将其与顶点D匹配时，就会出现问题. 我试图分别计算所有这些步骤，但是效率似乎很低.

But problems occur when I need to get also edges e1 and match them with vertices D. I tried to compute all these steps separately, but is seems to be very inefficient.

您对使用gremlin-java或gremlin-groovy实施此方法(可能使用多个查询)有任何建议吗? 谢谢！

Do you have any suggestions how to implement this (maybe using several queries) using gremlin-java or gremlin-groovy? Thanks!

推荐答案

看看此处描述的模式匹配模式:

Take a look at the Pattern Match Pattern described here:

https://github.com/tinkerpop/gremlin/wiki/Pattern-匹配模式

startVertex.outE('e1').as('e')
.inV().hasProperty('number').inE("e2")
.outV().hasProperty("id")
.outE("e3")
.inV().hasProperty("number").as('d')
.table(t)

这应该提供地图的迭代器

This should give an iterator of maps

[e:e1, d:D]

从每张地图中，您都可以轻松提取感兴趣的属性.

From each of these maps, you can easily extract the properties you are interested in.

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