grep + grep + sed = sed:无输入文件 [英] grep + grep + sed = sed: no input files
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问题描述
有人可以帮我吗?
grep " 287 " file.txt | grep "HI" | sed -i 's/HIS/HID/g'
sed: no input files
也尝试过xargs
grep " 287 " file.txt | grep HI | xargs sed -i 's/HIS/HID/g'
sed: invalid option -- '6'
这很好
grep " 287 " file.txt | grep HI
推荐答案
如果要保留管道:
f=file.txt
tmp=$(mktemp)
grep " 287 " "$f" | grep "HI" | sed 's/HIS/HID/g' > "$tmp" && mv "$tmp" "$f"
或者,简化:
sed -i -n '/ 287 / {/HI/ s/HIS/HID/p}' file.txt
这将过滤掉任何不包含"287"和"HI"的行-这就是您想要的吗?我怀疑您真的想要这个:
That will filter out any line that does not contain " 287 " and "HI" -- is that what you want? I suspect you really want this:
sed -i '/ 287 / {/HI/ s/HIS/HID/}' file.txt
对于与/ 287 /
匹配的行,请用大括号执行命令.在其中,对于与/HI/
匹配的行,搜索第一个"HIS"并替换为"HID".如果未指定-n
,则sed隐式打印所有行.
For lines that match / 287 /
, execute the commands in braces. In there, for lines that match /HI/
, search for the first "HIS" and replace with "HID". sed implicitly prints all lines if -n
is not specified.
其他执行相同操作的命令:
Other commands that do the same thing:
awk '/ 287 / && /HI/ {sub(/HIS/, "HID")} {print}' file.txt > new.txt
perl -i -pe '/ 287 / and /HI/ and s/HIS/HID/' file.txt
awk没有就地"选项(对于最新的gawk版本,gawk -i inplace
除外)
awk does not have an "in-place" option (except gawk -i inplace
for recent gawk versions)
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